In a labratory activity the density of a sample of vanadium is determined to be 6.9g/cm^3 at room temperature. what is the percent error for the determined value?

answers:
a : 0.15%
b : 0.87%
c : 13%
d : 15%

explain!

c : 13%

Explanation:

Data Give:

Experimental density of vanadium = 6.9 g/cm³

percent error = ?

Solution:

Formula used to calculate % error

  % error = [experimental value -accepted value/accepted value] x 100

The reported accepted density value for vanadium = 6.11 g/cm³

Put value in the above equation

                  % error = [ 6.9 - 6.11 / 6.11 ] x 100

                  % error = [ 0.79 / 6.11 ] x 100

                  % error = [ 0.129] x 100

                  % error = 12.9

Round to the 2 significant figure

% error = 13 %

So, option c is correct            

answer; /// i do believe that the correct answer is (a) boiling

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