Chemistry, 04.01.2020 02:31 Samuelgamboe

Compete the following table comparing atomic mass and mass number by enteng yes or no in each box.

Compete the following table comparing atomic mass and mass number by enteng yes or no in each box.<

Answers: 2

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Answer from: kkkhomewirk

atomic mass; mass number

1) NO ; YES

2) YES ; YES

3) YES ; YES

4) YES ; NO

5) NO; YES

Explanation:

An atomic mass is the mass of a single atom of a chemical element. It includes the masses of the 3 subatomic particles that make up an atom: protons, neutrons and electrons.

And also 1 atomic mass unit is defined as $\frac{1}{12}$ of the mass of a single carbon-12 atom.

Now, mass number of an element is the sum of protons and neutrons present in a single atom of that element.

Mass of the electrons is 9.10938356 × 10⁻³¹ kilograms

which is negligible.

And mass of proton and neutron is nearly but not exactly 1 u.

so, mass number is nearly but not exactly equal to atomic mass ,most of the times.

so,

1) only mass number can be used to calculate number neutrons present by simple subtracting atomic number(proton number) in mass number

2) both of these are found in periodic table

3) both can be found for individual atoms

4) mass number are different for isotopes but the atomic mass is calculated considering the isotopes(depends on availability of isotopes)

5)only mass number is given in isotopic symbol.

Answer from: Quest

Note that 2 mol dm⁻³ = 2 mol/(dm³)outline: we're given the concentration of hcl, which is 2 mol dm⁻³ (cubic meters in the denominator can represent volume, so i know this is concentration). we're an amount of calcium carbonate caco₃, which is 5 g. we're presented with a chemical equation which includes caco₃ and hcl. we are told to find the volume of hcl. from what we see so far, this seems to be a stoichiometry problem. we'll have to use the given information about calcium carbonate to find the amount of moles of hcl needed to fully react with calcium carbonate. then we'll have information about the moles of hcl and the concentration of hcl; that will be enough to figure out volume according to the formula concentration = moles / volume.======all the answer choices are not in dm.convert the given concentration so that it uses cm⁻³.we can use conversion factors. we have to cube our conversion factors so that dimensional analysis works.we can convert to meters first, using the fact that 10 dm = 1 m ⇔ 10³ dm³ = 1 m³then we use the fact that 10² cm = 1 m ⇔ (10² cm)³ = (1 m)³ ⇔ 10⁶ cm³ = 1 m³so converting: $\dfrac{\text{2 mol}}{\text{dm}^{3}} \cdot \dfrac{\text{10}^3\text{ dm}^3}{\text{1 m}^3} \cdot \dfrac{\text{1 m}^3}{10^6\text{ cm}^3} \\ \\ = \dfrac{\text{2 mol}}{1} \cdot \dfrac{\text{10}^3}{1} \cdot \dfrac{1}{10^6\text{ cm}^3} \qquad \text{\footnotesize cancelling units} \\ \\ = \dfrac{2\text{ mol}}{10^3 \text{ cm}^3} \\ \\ = 0.002\text{ mol/cm}^3$ now we have to find the moles of hydrochloric acid neededfind the moles of calcium carbonate. we have to find the molar mass of calcium carbonate, caco₃, which can be found by molar mass = (mass ca) + (mass c) + 3(mass o) = 40 + 12 + 3(16) = 100 g/molconvert the given 5 g to moles: mol caco₃ = 5 g caco₃ * 1 mol/(100 g) = 0.05 mol caco₃use stoichiometry (ratios) to figure out the moles of hcl needed. ratio wise, there's 2 hcls for every caco₃, so use dimensional analysis mol hcl = mol caco₃ * (2 mol hcl) / (1 mol caco₃) = 0.05 mol hcl * 2 = 0.1 mol hcl we have 0.1 mol hcl and concentration of hcl (0.002 mol/cm³).we need to find volumesince concentration = moles / volume, rearrange to get volume = moles / concentration volume = 0.1 mol / (0.002 mol/cm³) volume = 50 cm³

Answer from: Quest

the correct answer is c

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Compete the following table comparing atomic mass and mass number by enteng yes or no in each box.

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