Which of the following numerical expressions gives the number of particles in 2.0 g of ne?
a. 6.0 x 10^23 particles/mol / 2.0 g
b. 6.0 x 10^23 particles/mol / 20.18 g/mol
c. 2.0 g (6.0 x 10^23 particles/mol) / 20.18 g/mol
d. 20.18 g/mol (6.0 x 10^23 particles/mol) / 2.0 g

Number of particles = 2.0 g*(6.0 x 10^23 particles/mol) / 20.18 g/mol

Option C is correct

Explanation:

Step 1: Data give

Mass of Ne = 2.0 grams

Molar mass of neon = 20.18 g/mol

Number of Avogadro = 6.0 *10^23 /mol

Step 2: Calculate number of moles of neon

Moles Ne = Mass of ne / Molar mass of ne

Moles Ne = 2.0 / 20.18 g/mol

Moles Ne = 0.099 moles

Step 3: Calculate nulber of particles

Number of particles = 6.022*10^23 / mol * 0.099 moles = 5.96 *10^22

Number of particles = 6.022*10^23 * (2.0g/ 20.18g/mol)

Number of particles = 2.0 g*(6.0 x 10^23 particles/mol) / 20.18 g/mol

Option C is correct

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