Which of the following correctly provides the name of the element, the symbol for the ion, and the name of the ion? a) fluorine, f, fluoride ionb) sulfur, s, sulfurous ionc) copper, cu, cuprous iond) zinc, zn, zincate ion

Option (a) is the correct answer.

Explanation:

When a non-metal gains an electron then it acquires a negative charge and when a metal loses an electron then it acquires a positive charge.

According to the IUPAC nomenclature, when a non-metal gains an electron then a suffix "-ide" is added at the end of the name of the ion. Whereas generally when a metal loses an electron then no suffix is added to its name but there are some exceptions.

For example, fluorine is a non-metal and when it gains one electron then it forms ion which is known as the fluoride ion. Similarly, sulfur on gaining two electrons form ion which is known as sulfide ion.

Copper on loosing one electron forms ion and it is known as cuprous ion or copper(I) and not Cu.

Thus, we can conclude that out of the given options fluorine, F, fluoride ion correctly provides the name of the element, the symbol for the ion, and the name of the ion.

answer : (a) volume of the gas = 8.67 ×   l

                (b) second virial coefficient b = -1.21226 l/mole

solution :   given,     t = 300k

                                p = 20atm

                                z = 0.86

                                n = 8.2 mmoles = 8.2 × moles

                                r =   0.082 l atm/k/mol

        find,     (a) volume of gas   and (b) second virial coefficient b at 300k.

formula used :            

                          and            

(a)            

                    = \times 0.082\times 300}{20}[/tex]

                    = 8.67 ×   l

(b)      

                    = (0.00867-1) × 8.659

                    = - 8.5839 l/mole

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explanation:

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