Calculate the lattice energy of kcl(s) given the following data using the born-haber cycle: δhsublimation k = 79.2 kj/mol ie1 k = 418.7 kj/mol bond energycl–cl = 242.8 kj/mol eacl = 348 kj/mol δhkcl(s) = –435.7 kj/mol

Explanation:

  The following equation relates to Born-Haber cycle

Where

is enthalpy of formation

S is enthalpy of sublimation

B is bond enthalpy

is ionisation enthalpy of metal

is electron affinity of non metal atom

is lattice energy

Substituting the given values we have

-435.7 = 79.2 + 1/2 x 242.8 + 418.7 - 348 +U_L

= - 707 KJ / mol