Calculate the ph of a buffer solution prepared by dissolving 0.20 mole of cyanic acid (hcno) and 0.80 mole of sodium cyanate (nacno) in enough water to make 1.0 liter of solution. [k a(hcno) = 2.0 × 10 −4] 0.97 3.10 4.40 3.70 4.30

Option (e) is the correct answer.

Explanation:

Equilibrium reaction equation for the given reaction is as follows.

It is given that initial moles of HCNO is 0.20 mol and for NaCNO is 0.80 mol. of HCNO is mol.

Now, we will assume that at equilibrium there are x moles.

Initial:        0.20                           0.80              0

Change:      -x                              +x                +x

Equilibrium: 0.20 - x                 0.80 + x           x

As the volume of the given solution is 1 liter, equilibrium concentration and moles are same.

              x = M

Then, pH =

               =

               = 4.30

Thus, we can conclude that pH of given buffer solution is 4.30.

the electron configuration that you gave me has 16 electrons ergo it has 16 protons ergo it is the element sulfur.