200.0 ml of 0.778 m solution is diluted to 1.00 l. what is the molarity of the new solution? m (report your answer with the correct sig figs in units of moles/ l, m)

The answer to your question is C₂ = 0.16 M

Explanation:

Data

Volume 1 = V1 = 200 ml

Concentration 1 = C1 = 0.778 M

Concentration 2 = C2 = ?

Volume 2 = 1 l

Formula

               C₁V₁  =  C₂V₂

Solve for C₂

               C₂ = C₁V₁ / V₂

Process

1.- Convert volume 1 to liters

               1000 ml  1 l

                 200 ml  x

                 x = (200 x 1) / 1000

                 x = 200 / 1000

                 x = 0.20 l

2.- Substitute the values in the formula

                 C₂ = (0.778 x 0.20) / 1

3.- Simplification and result

                  C₂ = 0.156 M

the answer would be b i believe