For the reaction n₂(g) + 3h₂(g) ⇌ 2nh₃(g) what is the value of kc at 500 ∘c if the equilibrium concentrations are as follows:
[h₂] = 0.50 m , [n₂] = 0.50 m , and [nh₃] = 2.1 m ?
express the equilibrium constant to two significant figures.

Kc = 70

Explanation:

This is the reaction:

N₂(g) + 3H₂(g) ⇌ 2NH₃(g)

Let's make the expression for K, with concentration at equilibrium and in molarity.

Kc = [NH₃]²  /  [H₂]³ . [N₂]

Kc = (2.1)² / (0.5)³ . 0.5

Kc = 4.41 / 0.0625 → 70

quartz

explanation:

in scientific notation, the value of the  speed of light in a vacuum

  will be written as 2.995 * 10^8. when this value is represented in the form of

  a * 10^b, then, a = 2.995 and b = 8.

the value of the speed of light in a vacuum given above can also be rounded up to approximately 300000000. in this case, the scientific notation will be written as 3 *10^8.