Acontainer of nitrogen gas at 23 degrees celcius contains 425 l at a pressure of 3.5 atm. if 26.6 kj of heat are added to the container, what will be the new temperature of the gas?

75°C

Explanation:

From the general gas equation: P1V1/T1 = P2V2/T2

P1 = 3.5atm = 3.5×101.325KN/m^2 = 354.64KN/m^2, V1 = 425L = 425/1000 = 0.425m^3, E1 = P1V1 = 354.64×0.425 = 150.722KJ, T1 = 23°C = 23 + 273K= 296K

E2 = P2V2 = 26.6 + E1 = 26.6 + 150.722 = 177.322KJ

T2 = (E2 × T1)/E1 = (177.322 × 296)/150.722 = 348K

T2 = 348 - 273 = 75°C

New temperature of the gas is 75°C

the answer your looking for is c).