2-chloropropane is treated with naoh. of the following, the most likely product to form would be a(n):
a. primary alcohol.
b. secondary alcohol.
c. aldehyde.
d. ketone.

secondary alcohol

Explanation:

NaOH in solution provides OH- nucleophile.

When 2-chloropropane is treated with NaOH, nucleophillic substitution reaction takes place.Here leaving group is Chlorine atom (Cl).

Here OH- replaces Chlorine (Cl) to form 2-propanol which is a secondary alcohol.(OH group attached to 2° carbon)

Other possibility is elimination reaction in which NaOH acts as base.

NaOH acts as base when it is concentrated and aqueous NaOH acts as nucleophile.

In that case,the product formed will be an alkene.(not there in option)

hi,

the capital city of australia is canberra.

first let us lay out the formula for potential

and kinetic energy:

pe = mgh

ke = (mv^2)/2

where: m=mass, v=velocity, g=gravitational

acceleration, h=height

calculating for mass using the known values of

pe:

340j = m (9.81 m/s^2) (50ft) (1m/3.28ft)

m = 2.27 kg

the law of conservation of energy states that

energy is neither created nor destroyed. therefore, the change in kinetic

energy from 50 ft to 35 ft would be equal to the change in potential energy

from 50 ft to 35 ft. however it would be opposite in signs since one is losing

while other is gaining.

ke(35ft) – ke(50ft) = - [ pe(35ft) – pe(50ft]

ke(50ft) = 0 since the brick is initially at rest

ke(35ft) = 340j - 2.27kg (9.81 m/s^2) (35ft)

(1m/3.28 ft)

ke(35ft)

= 102.38 j