When 1 mol each of c2h5oh and ch3co2h are allowed to react in 1 l of the solvent dioxane, equilibrium is established when 13 mol of each of the reactants remains. calculate the equilibrium constant for the reaction. (note: water is a solute in this reaction.)

Explanation:

The correct statement is:

When 1 mol each of C₂H₅OH and CH₃CO₂H are allowed to react in 1 L of the solvent dioxane, equilibrium is established when 1/3 mol of each of the reactants remains. Calculate the equilibrium constant for the reaction. (Note: Water is a solute in this reaction.)

1. Equilibrium equation

               ↑                  ↑                          ↑                    ↑

          ethanol     acetic acid        ethyl acetate       water

2. Equilibrium constant

Since water is also a solute in this reaction (the solvent is dioxane) its concentration will appear in the equilibrium constant.

3. Equlibrium concentrations:

Moles

                  C₂H₅OH + CH₃CO₂H     ⇄    CH₃CO₂C₂H₅ +   H₂O

Initial                1                  1                                 0                  0

Change          -2/3            -2/3                            +2/3             +2/3

End                  1/3               1/3                              2/3              2/3

Since the volume is 1 liter, the concentration is equal to the number of moles

4. Calculations:

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the seeing the electronic configuration we can say that the element is fluorine.

fluorine is the most electronegative element in the periodic table.

but by only seeing the configuration we cannot say about its reactivity because we don't know if its configuration after excitation or by addition of electrons.

but if not then, it is the lightest halogen and exists as a highly toxic pale yellow diatomic gas at standard conditions. as the most electronegative element, it is extremely reactive: almost all other elements, including some noble gases, form compounds with fluorine.