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Chemistry, 26.12.2019 02:31 AliMe52

P4o10(s) = -3110 kj/mol h2o(l) = -286 kj/mol h3po4(s) = -1279 kj/mol calculate the change in enthalpy for the following process: p4o10(s) + 6h2o(l) → 4h3po4(s)

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P4o10(s) = -3110 kj/mol h2o(l) = -286 kj/mol h3po4(s) = -1279 kj/mol calculate the change in enthalp...
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