How many water molecules are produced in the complete neutralization of one mole of phosphoric acid with potassium hydroxide

Three (3) molecules of water (H2O)

Explanation:

Phosphoric acid = H3PO4

Potassium hydroxide = KOH

Chemical equation is as follows:

H3PO4 + 2KOH --> K2HPO4 + 2H2O (incomplete neutralization yields 2 molecules of water)

K2HPO4 + KOH --> K3PO4 + H2O (complete neutralization 1 molecule of water)

Total water molecules released is 3

a: 45.9 meters

b: 4.29 seconds

step-by-step explanation:

a: h(t)=1/2(-9.8)(3)^2+0(3)+90

h(t)=-4.9(3)^2+90

h(t)=-44.1+90

h(t)=45.9 meters

b: 0=1/2(-9.8)(t^2)+0t+90

0=-4.9t^2+90

-90=-4.9t^2

18.37=t^2

t=4.29 seconds

in the second question, the numbers aren't exact, but they're a close approximation.

can you list the answers so i can answer