Using the reagents below, list in order (by letter, no period) those necessary to transform 1-chlorobutane into 1-butyne. note: not all entry-fields provided may be needed. choose "na" in any space where you have no reagent. a. h2, ni b. h2, pd/caso4, quinoline c. h2, ni2b(p-2) d. br2 e. nanh2, mineral oil, heat f. nh4cl g. t-buok, t-buoh, heat h. ch3i i. ch3ch2i

Explanation:1. NaNH2 (1-Butene)

CH3CH2CH2CH2Cl > CH3CH2CH=CH2 + HCl (elimination reaction)

2. Br2, CCl4

CH3CH2CH=CH2 > CH3CH2CH(Br)CH2Br (Simple addition Reaction)

3. NaNH2 (1-Butyne)

CH3CH2CH(Br)CH2Br > CH3CH2C≡CH + 2HBr

Sodamide (NaNH2) is a very strong base and generally results in Terminal Alkynes when treated with Vicinal Dihalides.

Alcoholic KOH on the other hand results in the formation of Alkynes with triple bonds in the middle of the molecule.

answer: -

reaction:

na + cl ⇌ nacl

balanced chemical equation:

na + 2cl ⇌ nacl2

sodium + clorine goes to form sodium chloride (table salt).

the product is nacl2.

and the reactants are na and cl.

(note: if you don’t know what ⇌ means, read below: -

⇌(double head arrow) means reversible reaction).