Given the following reaction: \ce{cu + 2agno3 -> 2ag + cu(no3)2}cu+2agno3 2ag+cu(nox 3 )x 2 how many moles of \ce{ag}aga, g will be produced from 16.0 \text{ g}16.0 g16, point, 0, start text, space, g, end text of \ce{cu}cuc, u, assuming \ce{agno3}agno3 is available in excess

0.252 mol

Explanation:

Given the following reaction:

Cu + 2 AgNO₃ → 2 Ag + Cu(NO₃)₂

How many moles of Ag will be produced from 16.0 g Cu, assuming AgNO3 is available in excess.

First, we write the balanced equation.

Cu + 2 AgNO₃ → 2 Ag + Cu(NO₃)₂

We can establish the following relations.

The moles of Ag produced from 16.0 g of Cu are:

Explanation:

Hello,

In this case, the undergoing chemical reaction is:

As the silver nitrate is in excess, the yielded moles of silver are computed from the 16g of copper as shown below, including the corresponding stoichiometric 1 to 2 relationship between copper and silver respectively:

Best regards.

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a is the correct answer