If 5.0 g of each reactant were used for the the following process, the limiting reactant would be: 2kmno4 + 5hg2cl2 + 16hcl -> 10hgcl2 + 2mncl2 + 2kcl + 8h2o (kmno4 mm=158 g/mol; hg2cl2 mm=472.1 g/mol; hcl mm=36.5 g/mol; hgcl2 mm=271.5 g/mol; mncl2 mm=125.8 g/mol; kcl mm=74.6 g/mol; h2o mm=18 g/mol) *
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Chemistry, 21.06.2019 20:00
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An atom's configuration based on its number of electrons ends at 3p4. another atom has seven more electrons. starting at 3p, what is the remaining configuration? 3p63d34s2 3p43d54s2 3p64s23d3 3p44s23d
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If 5.0 g of each reactant were used for the the following process, the limiting reactant would be:...
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