The thermochemical equation for the combustion of rubbing alcohol is 2c3h7oh (l) + 9o2 → 6co2 +8h2o(l) δh = -474.8 kj calculate the amount of heat released when 25.0 g of rubbing alcohol is combusted.

Amount of heat released when 25.0 g of (rubbing alcohol) is combusted equal to 98.7 kJ

Explanation:

According to balanced equation (as given in problem), combustion of 2 moles of rubbing alcohol release 474.28 kJ of heat.

Molar mass of (rubbing alcohol) = 60.095 g/mol

We know, number of moles of a compound is the ratio of mass to molar mass of that compound.

So, 2 moles of (rubbing alcohol) = (rubbing alcohol) = 120.19 g of (rubbing alcohol)

So, combustion of 120.19 g of rubbing alcohol release 474.28 kJ of heat.

Hence amount of heat released when 25.0 g of (rubbing alcohol) is combusted =