When the reaction begins, the researcher records that the rate of reaction is such that 1 mole of a is consumed per minute. after making changes to the reaction, the researcher notes that 2 moles of a are consumed per minute. what change could the researcher have made to effect this change?

a. utilize reaction conditions to convert both reactants to solids.
b. decrease the concentration of reactant b to allow c to be produced at a greater rate.
c. increase the temperature, allowing more frequent collisions of a and b with greater kinetic energy.
d. increase the concentration of c to allow for more frequent collisions of a and b of higher energy
e. introduce a catalyst to decrease the consumption of a and b.

C. Increase the temperature, allowing more frequent collisions of A and B with greater kinetic energy.

Explanation:

For the reaction:

A + B → 2C

You can increase the consume of A:

A. Utilize reaction conditions to convert both reactants to solids.  FALSE. Convert both reactants in solids makes less frequent collisions doing difficult the reaction.

B. Decrease the concentration of reactant B to allow C to be produced at a greater rate.  FALSE. The decreasing of B will make the reaction slowly.

C. Increase the temperature, allowing more frequent collisions of A and B with greater kinetic energy.  TRUE. The increase of temperature will make more frequent collisions of A and B doing the reaction faster.

D. Increase the concentration of C to allow for more frequent collisions of A and B of higher energy . FALSE. The increase of C makes less frequent collisions doing difficult the reaction.

E. Introduce a catalyst to decrease the consumption of A and B. FALSE. Introducing a catalyst increase the consumption of A and B.

I hope it helps!

if the concentration of products is decreased, the equilibrium will shift toward the products). add an inert gas (one that is not involved in the reaction) to the constant-volume reaction mixture: this will increase the total pressure of the system, but will have no effect on the equilibrium condition.

explanation: