An alternative definition of electronegativity is electronegativity= constant (i. e — e. a.) where i. e. is the ionization energy and e. a. is the electron affinity using the sign conventions of this book. use data in chapter 12 to calculate the (i. e. - e. a.) term for f, cl, br, and i. do these values show the same trend as the electronegativity values given in this chapter? the first ionization energies of the halogens are 1678, 1255, 1138, and 1007 kj/mol, respectively.

The electronengativity values of given elements is as follows.

Fluorine - 4

Chlorine -3

Bromine - 2.9

Iodine- 2.5

Explanation:

Electronegativity  =consant (I.E-E.A)

The electron affinity and ionization energy values of the given elements is as follows.

(In attachment)

First we have to find the value of constant by using the fluorine atom to whom the electronengativity taken as "4".

Fluorine:

By using this constant values we can find electronegatvity values of remaining elements.

Chlorine:

Therefore, electronegativity of chlorine is 3.

Bromine:

Therefore, electronegativity of bromine is 2.9.

Iodine:

Therefore, electronegativity of iodine is 2.5.

a corroding iron, if that's one of your choices

hydrocarbons are organic compounds that contain only hydrogens and carbons. they can be saturated (those which contain only carbon-carbon single bonds) or unsaturated (those which contain carbon-carbon double or triple bonds) in nature. hydrocarbons can undergo several reactions like substitution, elimination etc.  

on substituting one or more hydrogen atoms in hydrocarbon it results in the formation of haloalkane. as the halogen atoms are large compared to the carbon and hydrogen atoms, due to which the molecular weight increases and the bond become polar because of presence electronegative halogen atom and results in the increase in boiling point of the haloalkane.

thus, the correct option is (b) that is the boiling point of the new compound increases on substituting a hydrogen atom with a halogen in a hydrocarbon.