An optically active alkyne a (c10h14) can be catalytically hydrogenated to butylcyclohexane. treatment of a with c2h5mgbr liberates no gas. catalytic hydrogenation of a over pd/c in the presence of quinoline poison and treatment of the product b with o3 and then h2o2 gives an optically active tricarboxylic acid c8h12o6. (a tricarboxylic acid is a compound with three

Ibelieve it's celsius. hope this .

Answer is: the equilibrium  shifts toward the reactants, to the left side of chemical reaction.it is because lead(ii) nitrate dissociates in water: pb(no₃)₂ → pb²⁺(aq) + 2no₃⁻(aq).according to lechatelier's principle, the position of equilibrium moves to counteract thechange (more lead cations, common ion), the position of equilibrium will move so that the concentration ofproducts decrease and concentration of reactants of chemical reaction increase.read more on -