An optically active compound a, c6h10o2, when dissolved in naoh solution, consumed one equivalent of base. on acidification, compound a was slowly regenerated. treatment of

a. with lialh4 in ether followed by protonolysis gave an optically inactive compound
b. that reacted with acetic anhydride to give an acetate diester derivative
c. compound b was oxidized by aqueous chromic acid to β-methylglutaric acid (3-methylpentanedioic acid),
d. identify compounds a, b, and c; do not specify stereochemistry. (the absolute stereochemical configurations of chiral substances cannot be determined from the data.)

Which best describes how johannes kepler developed his laws of planetary motion

Two nitro no2 groups are chemically bonded to a patch of surface. they can't move to another location on the surface, but they can rotate (see sketch at right). it turns out that the amount of rotational kinetic energy each no2 group can have is required to be a multiple of ε, where =ε×1.010−24 j. in other words, each no2 group could have ε of rotational kinetic energy, or 2ε, or 3ε, and so forth — but it cannot have just any old amount of rotational kinetic energy. suppose the total rotational kinetic energy in this system is initially known to be 32ε. then, some heat is removed from the system, and the total rotational kinetic energy falls to 18ε. calculate the change in entropy. round your answer to 3 significant digits, and be sure it has the correct unit symbol.

A40 kilogram skier starts at the top of a 12 meter high slope. at the bottom, she is travelling 10 meters per second. how much energy does she lose to friction