For the elementary process n2o5(g)−→−no2(g)+no3(g) the activation energy (ea) and overall δe are 154kj/mol and 136kj/mol, respectively. (a) sketch the energy profile for this reaction, and label ea and δe. (b) what is the activation energy for the reverse reaction?

i'm pretty sure its b i might be wrong though!

i would say b

explanation:

but i think i would need more information than that

hydrocarbons are organic compounds that contain only hydrogens and carbons. they can be saturated (those which contain only carbon-carbon single bonds) or unsaturated (those which contain carbon-carbon double or triple bonds) in nature. hydrocarbons can undergo several reactions like substitution, elimination etc.  

on substituting one or more hydrogen atoms in hydrocarbon it results in the formation of haloalkane. as the halogen atoms are large compared to the carbon and hydrogen atoms, due to which the molecular weight increases and the bond become polar because of presence electronegative halogen atom and results in the increase in boiling point of the haloalkane.

thus, the correct option is (b) that is the boiling point of the new compound increases on substituting a hydrogen atom with a halogen in a hydrocarbon.