Suppose you are titrating an acid of unknown concentration with a standardized base. at the beginning of the titration, you read the base titrant volume as 2.94 ml. after running the titration and reaching the endpoint, you read the base titrant volume as 16.47 ml. what volume of base was required for the titration?

The volume of base was required for the titration is 13,53mL

Explanation:

In a titration of an acid (HX) with a base (YOH), the reaction of neutralization is:

HX + YOH → YX + H₂O

In the burette you are adding base until all HX reacts. The addition of base is in volume.

If in the beginnig, the volume that you read of base is 2,94mL and at the endpoint you read a volume of 16,47mL. The volume you spent in the titration that is the same volume of base you required for the titration is:

16,47mL - 2,94mL = 13,53mL

I hope it helps!

The volume of base required for the titration is 13.53 mL

Titration is a method of quantitative analysis in Chemistry whereby the unknown concentration of a substance A (known as titrand) is determined by measuring the volume of A  that is required to react completely with another substance B (known as titrant) of known concentration and volume.

The Initial and final volumes of the solutions used are recorded.

The volume of the solutions used are  determined by subtracting the Initial volume from final volume

Volume of Base/Acid used = Final volume - Initial volume

From the question; Final volume of base =  16.47 mL;

Initial volume of base = 2.94 mL

Volume of base required = 16.47 -  2.94 = 13.53 mL

Learn more here:

120,630,890

step-by-step explanation:

110+10=120,620+10=630,880+10=890

the right answer is c i just did the question.