Asample of methane at a pressure of 1.00 atm and a temperature of 93.1 k is heated at constant pressure to a temperature of 158 k. which of the following are true? choose all that apply

a. the liquid initially present will solidify.
b. the final state of the substance is a gas.
c. the sample is initially a solid.
d. the sample is initially a liquid. one or more phase changes will occur.

b. The final state of the substance is a gas.

d. The sample is initially a liquid. One or more phase changes will occur.

Explanation:

Methane has the following properties:

*"Normal" refers to normal pressure (1 atm).

According to this, we can affirm:

A sample of methane at a pressure of 1.00 atm and a temperature of 93.1 K is heated at constant pressure to a temperature of 158 K. Which of the following are true? Choose all that apply.

a. The liquid initially present will solidify.  FALSE. The liquid will vaporize.

b. The final state of the substance is a gas.  TRUE.

c. The sample is initially a solid.  FALSE. The sample is initially a liquid.

d. The sample is initially a liquid. One or more phase changes will occur. TRUE.

answer: - 3.) the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.

solution: - as per the rules, oxidation number of oxygen in its compounds is -2. the sum of oxidation numbers of all the elements of a molecule or compound is zero.

also, the oxidation number in elemental form is zero.

in no, the oxidation number of o is -2 so the oxidation number of n is +2 so that the sum is zero.

similarly, the oxidation number of c in co is +2 and o is -2.

on product side the oxidation number of n is 0 as it is in the elemental form() .

oxidation number of c in carbon dioxide is +4 as there are two oxygen in it and we know that each oxygen is -2.

so, oxidation number of n is changing from +2 to 0 and the oxidation number of c is changing from +2 to +4.

since nitrogen is reduced and hence no is acting as an oxidizing agent. carbon is oxidized and so co is acting as a reducing agent.

so, the right choice is number 3.)the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.