The concentration of a certain sodium hydroxide solution was determined by using the solution to titrate a sample of potassium hydrogen phthalate (khp).

in the titration, 20.46 ml of the naoh solution was required to react with 0.1082g khp.

calculate the molarity of the base.

[ NaOH ] = 0.026 M

Explanation:

∴ Vsln = 20.46 mL = 0.02046 L

∴ Mw KH(KHC8H4O4) = 204.24 g/mol

⇒ mol KHP = 0.1082 g / 204.24 g/mol = 5.298 E-4 mol

⇒ mol NaOH = (5.298 E-4 mol KHP)( mol NaOH/mol KHP)

⇒ mol NaOH = 5.298 E-4 mol

⇒ [ NaOH ] = 5.298 E-4 mol / 0.02046 L

⇒ [ NaOH ] = 0.026 mol/L = 0.026 M

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