The reaction 2nobr (g) → 2 no (g) + br2 (g) is a second-order reaction with a rate constant of 0.80 m-1s-1 at 11 °c. if the initial concentration of nobr is 0.0440 m, the concentration of nobr after 6.0 seconds is

Answer : The concentration of NOBr after 6.0 seconds is, 0.036 M

Explanation :

The expression used for second order kinetics is:

where,

k = rate constant =

t = time = 6.0 s

= final concentration = ?

= initial concentration = 0.0440 M

Now put all the given values in the above expression, we get:

Therefore, the concentration of NOBr after 6.0 seconds is, 0.036 M

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120,630,890

step-by-step explanation:

110+10=120,620+10=630,880+10=890