At 40°c, 50g of kclo3 is dissolved in 100g of water, is this solution saturated, unsaturated, or supersaturated?

Supersaturated

Explanation:

Let's define the types of solutions in the context of this problem firstly:

An unsaturated solution is a solution in which addition of more solute would result in dissolution at a given specific temperature. That is, at , if we add more than 50 g of and it still dissolves in 100 g of water, then we have an unsaturated solution.A saturated solution is a solution in which we have a maximum amount of a solute that could possibly dissolve in a solvent at a given specific temperature. That is, at , if we add 50 g of and no more of it dissolves, then we have a saturated solution.A supersaturated solution is a solution in which we have a greater amount of solute dissolved than we could possibly dissolve under normal circumstances. Let's say that the solubility here is 50 g of in 100 g of water at . If we dissolve more than 50 g, then we have a supersaturated solution.

We need to use a solubility curve for salts given below. Notice that the intersection in the y-axis at is at about 14 g. This means a saturated solution would be obtained if 14 g of were dissolved in 100 g of water at this temperature. Anything above it would yield a supersaturated solution, below – an unsaturated solution.

Hence, we have a supersaturated solution.

60.0 - there are 3 significant numbers