Areaction of importance in the formation of smog is that between ozone and nitrogen monoxide described by o 3 ( g ) + no ( g ) ⟶ o 2 ( g ) + no 2 ( g ) the rate law for this reaction is rate of reaction = k [ o 3 ] [ no ] given that k = 2.55 × 10 6 m − 1 ⋅ s − 1 at a certain temperature, calculate the initial reaction rate when [ o 3 ] and [ no ] remain essentially constant at the values [ o 3 ] 0 = 7.34 × 10 − 6 m and [ no ] 0 = 6.99 × 10 − 5 m, owing to continuous production from separate sources.

1.31 × 10⁻¹⁵ M/s

Explanation:

Let's consider the following reaction.

O₃(g) + NO(g) ⟶ O₂(g) + NO₂(g)

The rate law is:

rate = 2.55 × 10⁻⁶ M⁻¹s⁻¹ [O₃].[NO]

where,

2.55 × 10⁻⁶ M⁻¹s⁻¹ is the rate constant (k)

[O₃] is the concentration of O₃ raised to the reaction order 1

[NO] is the concentration of NO raised to the reaction order 1

When [O₃] = 7.34 × 10⁻⁶ M and [NO] = 6.99 × 10⁻⁵ M, the rate of the reaction is:

rate = 2.55 × 10⁻⁶ M⁻¹s⁻¹ (7.34 × 10⁻⁶ M).(6.99 × 10⁻⁵ M) = 1.31 × 10⁻¹⁵ M/s

14,16 18 reacts with group

hey there!

mass = 6.75 g

volume =   9 cm³

therefore:

d = mass / volume

d   = 6.75 / 9

d = 0.7 g/cm³

answer b