5.
54g of mercury is heated from 25°c to195°c and absorbs 26110 joules of heat in
the process. calculate the specific heat capacity of mercury.

2.84 j/g.°C

Explanation:

Given data:

Mass of mercury = 54 g

Initial temperature = 25°C

Final temperature = 195°C

Heat absorbed = 26110 j

Specific heat of mercury = ?

Solution:

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

ΔT  = T2 - T1

ΔT  =  195°C -  25°C

ΔT  =  170 °C

Q = m.c. ΔT

c = Q / m. ΔT

c = 26110 j /54 g. 170 °C

c = 26110 j /9180 g.°C

c = 2.84 j/g.°C

the answer to this question is 3.

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