Apan containing 40 grams of water was allowed to cool from a temperature of 91 degrees c. if the amount of heat released is 1300 j, what is the final temp

Final temperature is 83.236 °C.

Explanation:

Let final temperature to be 'T'

There is a theorem :

ΔQ = m·s·ΔT

ΔQ : Heat exchange = -1300 J (it is negative because heat is released)

m : mass which exchanges heat = 40 grams

s : specific heat capacity of water = 4.186 J/grams °C = 1 Calories/grams °C

ΔT : Change in temperature = T - 91°

-1300 = 40 × 4.186 × (T-91)

first one is the correct answer

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