What is the volume of 0.80 grams of o2 gas at stp?
0.59 liters
0.56 liters
0.50 liters
0.47 liters

0.56 liters

Explanation:

At STP, one mole of a gaseous substance occupy 22.4 liters.

Hence 1 mole of oxygen gas will occupy 22.4 liters at STP.

We know that molar mass of oxygen is 32 g/mol.

So 32 grams of oxygen gas will occupy 22.4 liters at STP.

Then 0.8 grams of oxygen gas will occupy:

liters.

Hence the volume of 0.8 grams of oxygen gas at STP is 0.56 liters.

"you start with 15.67 g mgco3-xh2o, when heated and all the water is removed, you are left with 7.58 g mgco3 only.

therefore, you had 15.67 - 7.58 = 8.09g h2o  

moles of each :

7.58g mgco3 = ? moles = 7.58g / 83.4g/mole = 0.09moles  

8 09g h2o = ? moles = 8.09g / 18g/mole = 0.44moles  

molar ratio between the two by dividing both numbers by the smallest number :

0.09 / 0.09 = 1  

0.44 / 0.09 = 4.8  

mgco3-5h2o"