4. what coefficients would balance the equation below?
mg3p2 + lino3 → mg(no3)2 + li3p
a 16.32
b.
2.6.3.2
c. 1,3,3,2
d. 2,12,3,2

a. 1, 6, 3, 2

Explanation:

Reaction Given

              Mg₃P₂ + LiNO₃ → Mg(NO₃)₂ + Li₃P

Options Given

a. 1, 6, 3, 2

b. 2, 6, 3, 2

c. 1, 3, 3, 2

d. 2, 12, 3, 2

Solution:

Balance Chemical Equation:

A balanced chemical equation is that in which the number of the reactant atoms equal to the number of the product atom.

For example if the carbon at the reactant side is 3, the number of carbon must be 3 on the product side.

Check the chemical equation and count the number of atoms at the reactant side and product side.

If the number of atoms of the reactants equal to the number of atoms of products then the reaction is balanced but if not equal then reaction is not balanced

Balancing is an trial and error process to get a balance reaction.

First we count the number of atoms of reactant and product.

             Mg₃P₂ + LiNO₃ → Mg(NO₃)₂ + Li₃P

Number of atoms of Reactant:

Mg = 3

P = 2

Li = 1

N = 1

O = 3

Number of atoms of Product:

Mg = 1

P = 1

Li = 3

N = 2

O = 6

So the number of atoms on each side is not equal and we have to balance the given equation to get equal numbers of atom on reactant and product side

Check Option 1

a. 1, 6, 3, 2

             1 Mg₃P₂ + 6 LiNO₃ → 3 Mg(NO₃)₂ + 2 Li₃P

Now count the number of atoms of reactant and product.

Number of atoms of Reactant:

Mg = 3

P = 2

Li = 6

N = 6

O = 18

Number of atoms of Product:

Mg = 3

P = 2

Li = 6

N = 6

O = 18

So the reactants and product atoms are balanced now

So by putting numbers of option 1 as coefficient then the reaction get balanced no need to check other options.

i just calculated it all out, and not including weekends, and all the different days off. as of this school year (2018-2019) students are spending 2198 hours in school this year