Solutions of calcium phosphate and iron (iii) acetate are mixed to produce calcium acetate and iron (iii) phosphate

answer correctly for more points

The question has no question content. But let's do the balanced reaction.

Ca₃(PO₄)₂(aq) + 2Fe(C₂H₃O₂)₃(aq) → 3Ca(C₂H₃O₂)₂(aq) + 2FePO₄(s)

Explanation:

The calcium phosphate is formed by the ions calcium (Ca²⁺) and phosphate (PO₄³⁻), so to do the compound we must replace the charges:

Ca₃(PO₄)₂.

The iron (III) acetate is formed by the ions iron(III) (Fe⁺³) and acetate C₂H₃O₂⁻, and its formula is Fe(C₂H₃O₂)₃.

The products of the reaction will be calcium acetate, Ca(C₂H₃O₂)₂, and iron (III) phosphate, FePO₄. Thus, the reaction is:

Ca₃(PO₄)₂(aq) + Fe(C₂H₃O₂)₃(aq) → Ca(C₂H₃O₂)₂(aq) + FePO₄(s)

To be balanced, the amount of the elements must be the same on both sides of the reaction. Som we multiply Ca(C₂H₃O₂)₂ by 3, and Fe(C₂H₃O₂)₃(aq) and FePO₄ by 2:

Ca₃(PO₄)₂(aq) + 2Fe(C₂H₃O₂)₃(aq) → 3Ca(C₂H₃O₂)₂(aq) + 2FePO₄(s)

The acetates are soluble, and calcium is not an exception, so it will be in aqueous phase; the phosphates are insoluble, calcium is an exception, but iron (III) is not, so it will precipitate.

answer : (a) volume of the gas = 8.67 ×   l

                (b) second virial coefficient b = -1.21226 l/mole

solution :   given,     t = 300k

                                p = 20atm

                                z = 0.86

                                n = 8.2 mmoles = 8.2 × moles

                                r =   0.082 l atm/k/mol

        find,     (a) volume of gas   and (b) second virial coefficient b at 300k.

formula used :            

                          and            

(a)            

                    = \times 0.082\times 300}{20}[/tex]

                    = 8.67 ×   l

(b)      

                    = (0.00867-1) × 8.659

                    = - 8.5839 l/mole