The density of solid ag is 10.5 g/cm3. how many atoms are present per cubic centimeter of ag?

as a solid, ag adopts a face-centered cubic unit cell. how many unit cells are present per cubic centimeter of ag?

what is the volume of a unit cell of this metal?

what is the edge length of a unit cell of ag?

break it down to me step-by-step, so i can understand it.

Unit cells which are present per cubic centimeter of Ag =

Volume =

Edge length =

Explanation:

(a)

Given that:-

The density of the solid Ag = 10.5 g/cm³

Molar mass of silver = 107.8682 g/mol

So, Moles present per cm³ of Ag = =0.0973 mol/cm³

Also, 1 mole = atoms.

So,

Atoms present per cm³ of Ag =

Thus, answer =

In FCC, the number of atoms  in the unit cell = 4 unit cells

So,

Unit cells which are present per cubic centimeter of Ag =

Unit cells which are present per cubic centimeter of Ag =

(b)

The reciprocal of the unit cell/cm³ is the volume of the unit cell.

So,

Volume =

(c)

Also, Volume =

Thus, edge length = =

Edge length =

its first and third is your answer i did the qustion the fourth isnt right