The gas in a cylinder has a volume of 8 liters at a pressure of 104 kpa. the pressure if the gas is increased to 200 kpa. assuming the temperature remains constant, what woyld the new volume be?

To solve this we assume that the gas is an ideal gas. Then, we can use the ideal gas equation which is expressed as PV = nRT. At a constant temperature and number of moles of the gas the product of PV is equal to some constant. At another set of condition of temperature, the constant is still the same. Calculations are as follows:

P1V1 =P2V2

 V2 = P1 x V1 / P2

 V2 = 104 x 8 / 200

 V2 =4.16 L

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