Calculate e degree for the following half-reaction, fes(s) + 2e^- fe(s) + s^2^-(aq) given that the solubility product for fes at 25 degree c is 8.0 times 10^-19 and the standard reduction potential of the half-reaction shown is -0.440 v. fe^2+(aq) + 2e^- fe(s) construct the line notation of a cell that consists of a saturated calomel reference electrode, the fes half-reaction shown at the top of the problem, and an iron indicator electrode, which can be used to measure the s^2- concentration of a solution if the cell described by the line notation above has a potential of -1.035 v, what is the ps of the solution?

2h2o2--> 2h2o + o2

this reaction is of the spontaneous decomposition of hydrogen peroxide down into water and oxygen.

add 2 molecules of hydrogen peroxide and 2 molecules of water. since oxygen is naturally diatomic, the total number of atoms of each element is now the same on both sides of the equation so it is balanced.

this may not be entirely correct but let me know.

im pretty sure its b

substituting a hydrogen atom with a halogen in a hydrocarbon:

- the single bond remains single. a is wrong.

- the bond with hydrogen is as strong as with a halogen. c is wrong

- a hydrocarbon is saturated if there is no double bond. we do not know that so d is wrong.

- carbon will always have four valence electrons. e is wrong.

by elimination, the correct answer is b. the boiling point of the new compound increases.