Each of the following nuclides is known to undergo radioactive decay by production of a beta particle, 0.1e. write a balanced nuclear equation for each process. (use 'e' for an electron, p' for a positron, and 'n' for a neutron. omit states-of-matter from your answer.) (a) 146c chempad greek (b) 14055cs chempad greek. (c) 23490 th chempad need ? i̇.med. loen" l submit answer save progress

(a)   ¹⁴₆ C ⇒         ¹⁴₇ N +  ⁰₋₁ e

(b) ¹⁴⁰₅₅ Cs ⇒  ¹⁴⁰₅₆ Ba + ⁰₋₁ e

(c) ²³⁴₉₀ Th ⇒  ²³⁴₉₁ Pa + ⁰₋₁ e

Explanation:

In a beta decay the nuclide emits a beta particle which are high enery electrons. The number of neutrons decreases by one and the atomic number increases also by one moving the nuclide one place to the right in the periodic table. The mass of the nuclide does not change since the mass of electron is negligible compared to the proton and neutron.

(a)   ¹⁴₆ C ⇒         ¹⁴₇ N +  ⁰₋₁ e

(b) ¹⁴⁰₅₅ Cs ⇒  ¹⁴⁰₅₆ Ba + ⁰₋₁ e

(c) ²³⁴₉₀ Th ⇒  ²³⁴₉₁ Pa + ⁰₋₁ e

answer:

the reaction is type of combination reaction.

explanation:

on the product side, there are 2 molecules of bonded to fe   which means one atom of fe are combined two molecules of . so, balanced chemical equation becomes :

this reaction follows the reaction type of combination reaction. a combination reaction is defined as chemical reaction in which reactants combines together to form a single product.