The 1h nmr signal for bromoform (chbr3) appears at 2065 hz when recorded on a 300−mhz nmr spectrometer. if the spectrum was recorded on a 200−mhz instrument, what would be the chemical shift of the chbr3 proton? enter your answer in the provided box.

The chemical shift (δ) for CHBr₃ proton = 6.88 ppm

Explanation:

In NMR spectroscopy, Chemical shift (δ) is expressed in parts per million (ppm) and is given by the equation:

                    ....equation (1)

Given: Observed frequency: ν₁ = 2065 Hz,

Spectrometer frequency: ν'₁ = 300 MHz, ν'₂ = 200 MHz

To calculate the chemical shift (δ) for the given CHBr₃ proton, we use the equation (1)

Since in NMR spectroscopy, chemical shift is a field independent scaling. Thus the value of the chemical shift of a given proton, such as CHBr₃ proton, is independent of the magnetic field strength of the spectrometer.

So the value of chemical shift of a given proton remains same when measured with a 300 MHz and 200 MHz NMR spectrometer.

Therefore, the chemical shift (δ) for CHBr₃ proton = 6.88 ppm

there are no statements provided but here is why:

sulfur belongs to group 16 because it can be found in nature whether it is in a free or combined state.

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