The volume of air in a diving bell changes as it descends into deep water. if the air in a diving bell occupies 9.50 l at 1.02 atm and 20.1 c what will be the volume of the air at 1.55 atm and 15.0 c

V₂ = 6.14 L

Explanation:

Given data:

Initial volume = 9.5 L

Initial pressure = 1.02 atm

Initial temperature = 20.1 °C (20.1 +273 = 293.1 K)

Final temperature = 15°C (15+273 = 288 K)

Final volume = ?

Final pressure = 1.55 atm

Formula:  

P₁V₁/T₁ = P₂V₂/T₂  

P₁ = Initial pressure

V₁ = Initial volume

T₁ = Initial temperature

P₂ = Final pressure

V₂ = Final volume

T₂ = Final temperature

Solution:

P₁V₁/T₁ = P₂V₂/T₂  

V₂ = P₁V₁T₂/T₁ P₂

V₂ = 1.02 atm × 9.50 L × 288 K / 293.1 K × 1.55 atm

V₂ = 2790.72 atm. L.K / 454.305 K. atm

V₂ = 6.14 L

in chemistry, adhesion and cohesion are attractive forces that exist between molecules. they hold the molecules together from each other. they are different in that adhesive force exists between molecules of different substance while cohesive force happens between molecules of same substance.

adhesion between water and glass causes water molecules at the edge of water and glass interface to climb up the wall in a narrow glass tube. this is called capillary action. cohesion is what gives glass its shape and causes water to form a droplet.