Consider a balloon filled with helium at the following conditions. 313 g he 1.00 atm 1910. l molar heat capacity = 20.8 j/degree c middot mol the temperature of this balloon is decreased by 41.6 degree c as the volume decreases to 1643 l with the pressure remaining constant. determine q, w, and delta e (in kj) for the compression of the balloon.

Answer : The value of q, w and ΔE in kilojoule are -67.7 kJ, 27.05 kJ and -40.65 kJ respectively.

Explanation :

Formula used :

where,

Q = heat at constant pressure = ?  

= change in enthalpy energy

n = number of moles of helium gas = 78.25 mol

Molar mass of He = 4 g/mole

= heat capacity at constant pressure =

= change in temperature =

Now put all the given values in the above formula, we get:

Now we have to calculate the work done.

Formula used :

where,

w = work done

p = pressure of the gas = 1 atm

= initial volume = 1910 L

= final volume = 1643 L

Now put all the given values in the above formula, we get:

conversion used : (1 L.atm = 101.3 J)

Now we  have to calculate the value of of the gas.

Therefore, the value of of the gas is -40.65 kJ.

first one is the correct answer