Chemistry, 10.12.2019 04:31 summerhumphries3

Given two half reactions as follows: a2+ → 2 a2+ + 3 e− 4 e− + b → b4− what would you multiply each half-reaction by, to cancel out the electrons?

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In order to cancel the electrons,. the oxidation half reaction must be multiplied by 4 and the reduction half reaction must be multiplied by 3.

Explanation:

Oxidation reaction is defined as the chemical reaction in which an atom looses its electrons. The oxidation number of the atom gets increased during this reaction.

$X\rightarrow X^{n+}+ne^-$

Reduction reaction is defined as the chemical reaction in which an atom gains electrons. The oxidation number of the atom gets reduced during this reaction.

$X^{n+}+ne^-\rightarrow X$

The half cell reactions for the above reaction follows:

Oxidation half reaction: $A_{2}^+\rightarrow 2A^{2+}+3e^-$

Reduction half reaction: $B+4e^-\rightarrow B^{4-}$

Thus, in order to cancel the electrons,. the oxidation half reaction must be multiplied by 4 and the reduction half reaction must be multiplied by 3.

Thus,

4*Oxidation half reaction: $4A_{2}^+\rightarrow 8A^{2+}+12e^-$

3*Reduction half reaction: $3B+12e^-\rightarrow 3B^{4-}$

Overall reaction:-

$4A_{2}^++3B\rightarrow 8A^{2+}+3B^{4-}$

Answer from: Quest

Answer: abeexplanation:

1. the question asks the most appropriate, which seems to rule out "all of the above." your choice appears to be the correct one.

2. the protocol described is good for identifying correlation, but not cause and effect. for cause/effect, you need to devise a protocol that will assign the treatment (or not) to groups that have essentially the same "demographics" with respect to all the other variables. your choice regarding control group seems appropriate. random assignment of treatment (choice d) may be appropriate also. (i think you can argue that b and d are just different descriptions of the same method.)

3. d will randomize the birds, but may not guarantee there are 10 in each group. e will do both, so seems the better choice.

comment on question 2

based on the problem statement, it seems clear that confident, attentive drivers are more likely to use daytime running lights. so, the protocol might need to be devised in such a way that the lights would be turned on or off without the driver's knowledge. (an attentive driver will figure it out.) assigning a confident, attentive driver to a group required to drive without running lights might mess with his/her confidence and attentiveness. you don't want your experiment to do that. (nor do you want the experiment to subject a driver to greater risk of accident as a consequence of driving without running lights.) experiments involving human safety are always problematic.

Answer from: Quest

The answer is !

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Given two half reactions as follows: a2+ → 2 a2+ + 3 e− 4 e− + b → b4− what would you multiply each...

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