Consider the fructose-1,6-bisphosphatase reaction. calculate the free energy change if the ratio of the concentrations of the products to the concentrations of the reactants is 21.1 and the temperature is 37.0 ° c ? δ g ° ' for the reaction is − 16.7 kj/mol . δ g = kj / mol

Answer : The value of is -8.84 kJ/mol

Explanation :

The formula used for is:

   ............(1)

where,

= Gibbs free energy for the reaction  = ?

=  standard Gibbs free energy  = -16.7 kJ/mol

R = gas constant =

T = temperature =

Q = reaction quotient = = 21.1

Now put all the given values in the above formula 1, we get:

Therefore, the value of is -8.84 kJ/mol

output?

explanation: