Astudent must use 220 ml of hot water in a lab procedure. calculate the amount of heat required to raise the temperature of 220 ml of water from 30.0 /c to 100.0 /c. c for water is 4.184 j/g cc

64,433.6 Joules

Explanation:

We are given;

We are required to calculate the amount of heat required to raise the temperature.

Q = mcΔT , where m is the mass, c is the specific heat, ΔT is the change in temperature.

Density of water is 1 g/mL

Thus, mass of water is 220 g

ΔT = 100°C - 30°C

    = 70°C

Therefore;

Amount of heat, Q = 220g × 4.184 J/g°C × 70°C

                               = 64,433.6 Joules

Thus, the amount of heat required to raise the temperature of water is 64,433.6 Joules

- "the choice that is not an indicator of a chemical change is "state of matter changes". more common than not, chemical reactions produce energy in the form of light or heat. along with energy, they also produce a new substance called the product that could be in any state of matter (solid, gas, or liquid)."

the atomic number will stay the same no matter how many electrons it has, so it doesn’t decrease nor increase. it’ll only change with a different number of protons