0.043 mol of a gas weighs 1.892 g. what is the density (in g/l) of this gas at 0.0°c and 9.55 psi? (1.0 atm = 14.7 psi)

1·276 g/L

Explanation:

Given

Number of moles of gas = 0·043

Mass of the gas = 1·892 g

Temperature of the gas = 273 K

Pressure of the gas = 0·65 atm

Assuming that the gas is ideal

Ideal gas equation is P × V = n × R × T

where

P is the pressure of the gas

V is the volume occupied by the gas

n is the number of moles of the gas

R is the ideal gas constant

T is the temperature of the gas

Let the volume of the gas be V L

From ideal gas equation

0·65 × V = 0·043 × 0·0821 ×273

∴ V = 1·483 L

Density is defined as mass per unit volume

Let the density of the gas be d g/L

∴ d = (mass of the gas) ÷ (volume of the gas)

d = 1·892 ÷ 1·483

∴ d ≈ 1·276 g/L

∴ Density of the gas at the given conditions is 1·276 g/L

u i forgot the answer?

both adhesion and cohesion are attractions.

they are different in that adhesion is the force of attraction between the molecules of two different substances, whereas cohesion is the force of attraction between molecules of the same substance.

possible examples include capillary action, in which the adhesion between water and glass causes the water to rise in a narrow tube against the force of gravity.

because of hydrogen bonding, water is extremely cohesive.

this causes molecules on the surface of water to be drawn inward, which is why drops of water form beads on smooth surfaces.

hope this .