How many milliliters of a 10.6 m naoh solution are needed to prepare 0.715 l solution of naoh with a concentration of 0.550 m?

The required volume of 10.6 M NaOH solution is 0.0317 L and the further calculation can be defined as follows:

Given that:

Molarity of concentrated NaOH solution = 10.6 M

Molarity of diluted NaOH solution = 0.550 M

Volume of diluted NaOH solution = 0.715 L

To find:

Volume of stock solution required.

Formula used to calculate the volume of stock solution is:

where, are the concentration and volume of stock solution and are the concentration and volume of diluted solution.

Put the values in the above formula:

So, the required volume of 10.6 M NaOH solution is 0.0371 L.

Learn more about dilution law: link

37.1mL

Explanation:

This is a simple dilution problem where you utilize the equation:

(C=Concentration, V=Volume)

C1V1=C2V2

10.6(y)=0.715x0.550 (Y is unknown because we are trying to find how much of the original solution we need to dilute to make the final solution)

The solve for y and you get

y= 0.0317 L but this is in L and we want mL so multiply by 1000 you get

y= 37.1mL

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