A1.40-l gaseous system absorbs 75 j of heat and expands its volume to 2.00 l against an external pressure of 1.02 atm. what is the change in internal energy for this process? 1 = 101.3 j

15.24 J is the change in internal energy for this process.

Explanation:

According to the first law of thermodynamics:-

Where,  

U is the internal energy

q is the heat

w is the work done

From the question,

q = + 75 J

(+ sign as the heat is being absorbed)

The expression for the calculation of work done is shown below as:

Where, P is the pressure

is the change in volume

From the question,  

= 2.00 - 1.40 L = 0.60 L

P = 1.02 atm

Also, 1 atmL = 101.3 J

So,  

(work is done by the system)

So,

15.24 J is the change in internal energy for this process.