Compound a, c6h8, absorbed 3 equivalents of h2 on catalytic hydrogenation over a pd/c catalyst to give b (c6h14). on ozonolysis, compound a gave, among other things, a ketone which was identified as acetone. on treatment with nanh2 in nh3, followed by addition of iodomethane, compound a gave a new hydrocarbon, c (c7h10). draw the structure of compound c.

The structural formula of Compound C is CH₂(CH)₅CH₃.

Explanation:

Compound A is an alkene called Hexatriene, that is, it has three double bonds within its structure. Hydrogen atom is removed when compound A reacts with NaNH₂ in ammonia. Further reaction with iodomethane replaces the hydrogen atom with a methyl group from the iodomethane to form compound C.

Here is the step-wise mechanism:

CH₂(CH)₄CH₂ (With NaNH₂ in NH₃)> CH₂(CH)₄CH⁻ + H⁺

CH₂(CH)₄CH⁻ + CH₃I (Iodomethane) > CH₂(CH)₅CH₃ + I⁻

Compound C is called 1, 3, 5-Heptatriene.

considering the question as per the attachment

here we can see that the radon nuclide has 222 as the atomic mass number and 86 as the atomic number.

when it undergoes nuclear fission it gives polonium which has atomic mass number as 218 and atomic number will be 84 along with a helium nucleus which has 4 atomic mass number and 2 as its atomic number.

222 = 218 + 4 (atomic mass number)

86 = ? + 2; therefore ? = 86-2 = 84.

the atomic mass number of polonium will be 84.