Ahot air balloon is filled with 1.13 × 10 6 l 1.13×106 l of an ideal gas on a cool morning ( 11 ∘ c ) . 11 ∘c). the air is heated to 127 ∘ c . 127 ∘c. what is the volume of the air in the balloon after it is heated? assume that none of the gas escapes from the balloon. l=

New volume = L

Explanation:

Using Charle's law  

Given ,  

V₁ = L

V₂ = ?

T₁ = 11 °C

T₂ = 127 °C  

The conversion of T( °C) to T(K) is shown below:

T(K) = T( °C) + 273.15  

So,  

T₁ = (11 + 273.15) K = 284.15 K  

T₂ = (127 + 273.15) K = 400.15 K  

Using above equation as:

New volume = L