Both compounds a and b have molecular formula c6h14. monochlorination of compound a results in the formation of two constitutional isomers. monochlorination of compound b results in the formation of four constitutional isomers. identify compounds a and b, and show the products of each monochlorination.

1) draw compound a and the products of its monochlorination.

2)draw compound b and the products of its monochlorination.

The name of the two compounds will be:

A :2,2-dimethylbutane

B:  3-methylpentane

Explanation:

The compounds are the isomers of  hexane as per the given molecular formula.

There is no unsaturation or no ring is present in the compound.

Constitutional isomers are the one which have different arrangement of chain.

The possible compounds are shown in the figure with the products of monochlorination of the two isomers.

Thus there are five possible isomers of hexane.

yea hi

explanation:

the reaction mixture contains some ammonia, plus a lot of unreacted nitrogen and hydrogen. the mixture is cooled and compressed, causing the ammonia gas to condense into a liquid. the liquefied ammonia is separated and removed. the unreacted nitrogen and hydrogen are then recycled back into the reactor .