Calculate the lattice energy for naf (s) given the following

sublimation of energy +109 kj/mol

hf for f (g) + 77 kj/mol

first ionization energy of na (g) +495

electron affinity of f(g) -328

enthalpy of formation of naf(s) -570 kj/mol

a. -177

b. 192

c. -804

d. -1047

e. -923

E

Explanation:

The lattice energy is the energy change when one mole of a crystal is formed from its components ions in its gaseous sate

Therefore lattice energy = heat of Sublimation+ ionization energy +electron affinity-(heat of formation)

Therefore lattice Energy =     109 +495 -328 +570.

Lattice energy = --923kjmol-1

answer; i believe the correct answer is (solid gold);

i'm assuming that the correct answer is indeed the first one/ "a"..